Nick is one voice for a particular point of view. And there are many voices with a contrary point of view. So tell me, which point of view is most responsible for keeping this thread alive?
Jeff
That reads like gobbledygook. Do you want to try again in clear English, even clear Canadian would do.
I am pointing out that two options, with the prize assigned at random has even odds.
The third option is shown to be a red herring. The important fact is that there is a choice from two to be made to conclude the game, and there is nothing to distinguish between them.
It really is quite difficult to build an ugly wooden boat.
The power of the web: Anyone can post anything on the web
The weakness of the web: Anyone can post anything on the web.
Nick is the most consistent voice with the wrong answer and the one implying that his better thinking abilities and university training make him correct.
nick is the only poster i have seen thus far calling for tom to close the thread
Simpler is better, except when complicated looks really cool.
There is something to distinguish between them and that is that one is the result of choosing one door and the other is the result of receiving two doors and showing a losing door.
It really is quite difficult to build an ugly wooden boat.
The power of the web: Anyone can post anything on the web
The weakness of the web: Anyone can post anything on the web.
close, but again you've made a fatal error..
"Event A" is NOT the opening of any door, or the showing of the goat in Monty's hand..
that event has no effect on any outcomes, except to illustrate that one door is a NON-FACTOR in the final outcome of the game
opening the door is a red herring and the sleight of hand
the magician has taken you in !
the first event (Event A in reference to Bayes' theorem) would be the first player's choosing of their FIRST door
the choice when the POOL of possibilities was THREE DOORS (1 in 3)
that first choice, at that moment, is the event that sets the probabilities for the rest of the game.
whatever prize or goat was behind that door at that moment can never move across the aisle to Monty's side or behind the two doors.
the hand has been dealt and will remain unchanged until a winner is declared.
the second event (that's B) is the second half of the game, when the player is asked to choose their door or Monty's
coelcanth, i don't think the basis of the game can be explained any more clearly
Simpler is better, except when complicated looks really cool.
It really is quite difficult to build an ugly wooden boat.
The power of the web: Anyone can post anything on the web
The weakness of the web: Anyone can post anything on the web.
I'd just like to add that it's midnight here, and my tablet is on 12% battery.
And is this really day three?
Goodnight, all.
Andy
"In case of fire ring Fellside 75..."
Another way of looking at it is if Monty doesn't open either of "his" doors but asks "Do you want to change from your door to the best option of my two doors?" If you swap, there is a 2/3 chance that one of his doors has the prize. As at least one of the doors must be non-optimal, Monty opening the non-optimal door doesn't make any difference to the game.
Likewise if Monty opens both of his doors and asks "do you want to swap to the best of these doors" you would want to change 2 out of three times.
So calling all STEM teachers, we need help! So this is a "word problem", I was taught the whole trick to "word problems" (real life stuff) is to construct the equation correctly. The proof is the equation itself, seem like a simple 2 stage, one line equation is all that is needed. The problem I have is how to express the subtraction of the choice that that is the less of the two remaining choices, I think what He really does is subtract the most valuable choice that is less than the grand prize. (So Bob Bubank could describe all the things America could just go out and buy). The odds will work out the same regardless which of the two algorithms are used as long as the grand prize is not subtracted from the remaining choices.
I can construct the whole thing in python with one line, but that really a computer command not a equation. The equation should express the odds of one or the other remaining choices as one can get the other by subtracting the one you have from 100.
Wow…. 20 pages.
I’ve been out for the last half dozen pages, so I’ll take a swing.
No one reads my sh!t anyways.
Nick,
If Monty was selecting from his two doors at random and happened to select a goat, then you would be correct, the odds of either door containing the car would be 50/50.
But he’s not. Monty knows the locations of the car and goats from the outset. The draw is only random for the contestant.
Once Monty makes the informed choice to remove a goat from his two, the remaining door now has the odds are locked in a 1/3 and 2/3.
what is the relationship that affects the outcome ?!??
don't you see it by now ?
by choosing the first door we have removed that one door from the pool of three !
that is exactly it !! that is the exact event that affects the outcome of the final choice
MONTY NOW ONLY HAS TWO DOORS FROM WHICH TO PICK THE PRIZE WHEREAS WE HAD THREE
that is why he has better odds than the first player
Last edited by coelcanth; 06-15-2022 at 07:20 PM.
no that's not it
as long as the contestant has to pick first, their door will always have worse odds than Monty's two doors
Monty is not cheating at the game and he's not 'removing' the goat from play
even with a 1 in 3 chance and without switching doors, the player will still win the prize sometimes, there's just a smaller chance
it's never 50/50
Flatus has the distinct odor of our last Pratus and Flotus
I have a separate question:
The Monty Hall fans are legendary. The participants are rabid.
If there was a double probability of winning the car if you switch, and since this problem has been published on the internet for a long time, and since the fans watch the show religiously, wouldn't every participant always switch to the point that the show would stop running this game? I don't think they have because I don't think the viewers have seen the pattern that some claim is so clear.
"Where you live in the world should not determine whether you live in the world." - Bono
"Live in such a way that you would not be ashamed to sell your parrot to the town gossip." - Will Rogers
"Those are my principles, and if you don't like them... well, I have others." - Groucho Marx
This simply has to be leg pulling. No-one could be so intentionality blind……could they?
Last edited by Decourcy; 06-15-2022 at 08:29 PM.
Correct.
Nick keeps saying it is between randomised events of equal probability and it isn't.
Monty opening one door showing a goat doesn't make any difference, but that could only be random if the the player picked the car to start with. Otherwise which door he opens is determined by the position of the car.
monty hall is dead.
long live the monty hall problem!
no, you and Nick are both stuck on the same point..
revealing a goat in the second round does nothing to affect the probability of a pick that was made in the past
thinking about the reveal as 'removing' that goat from play is probably the wrong way to go about it and that's what's confusing you.
revealing the specific location of the goat really makes no difference (we already knew Monty had to have AT LEAST ONE goat, right?)
the particular door that it is in has no effect on whether Monty has the prize or not
if we think of Monty's two doors as his entire hand we can say that his entire hand has a 2 in 3 chance of containing the prize
opening the one door means that entire 2 in 3 chance now rests on the only unopened door in Monty's hand
that is why his last door has a 2/3 chance and your one earlier pick has only a 1/3 chance of winning
The show has known about this for most of the show, I watched a show years ago where Monty Hall himself talked about it. And the internet was decades away! The idea the show has a problem with this is silly, they have loved it. The show is for advertisers to highlight their products while the audience is watching a show. This is the stuff dreams are made of for those guys!
I do think the equation is to subtract the highest priced prize that is less than the grand prize from the two remaining choices.
33%, best offer!
There's a lot of things they didn't tell me when I signed on with this outfit....
Also bear in mind that in the real Let's Make a Deal!, there's a whole lot more going on.
Monty sometimes offers cash up front to entice the contestant to switch (or not switch).
The lovely Carol Merrill pops up out of a trap at random with a cart carrying a box that might or might not contain something of value, and that gets figured into the equation, too: "Stick with the door you selected? Or switch to the box that the lovely Carol Merrill has for you?"
Sometimes, it's even, "You switch doors? Great! I've got another deal for ya -- the lovely Carol Merrill has just brought this box on stage. Would you be interested in switching to that?"
The "Monty Hall Problem" is the stripped-down minimal example for analysis.
You would not enjoy Nietzsche, sir. He is fundamentally unsound. — P.G. Wodehouse (Carry On, Jeeves)
How can the probabilities of choosing between 2 different doors be 30% and 50%?